How do you do *integer* exponentiation in C#?

Question

The built-in Math.Pow() function in .NET raises a double base to a double exponent and returns a double result.

W

Answer 1

I cast the result into int, like this:

double exp = 3.0;
int result = (int)Math.Pow(2.0, exp);

In this case, there are no rounding errors because base and exponent are integer. The result will be integer too.