Counting trailing zeros of numbers resulted from factorial

Question

I\'m trying to count trailing zeros of numbers that are resulted from factorials (meaning that the numbers get quite large). Following code takes a number, compute the facto

Answer 1

I had the same issue to solve in Javascript, and I solved it like:

var number = 1000010000;
var str = (number + '').split(''); //convert to string
var i = str.length - 1; // start from the right side of the array
var count = 0; //var where to leave result
for (;i>0 && str[i] === '0';i--){
    count++;
}
console.log(count) // console shows 4

This solution gives you the number of trailing zeros.

var number = 1000010000;
var str = (number + '').split(''); //convert to string
var i = str.length - 1; // start from the right side of the	array
var count = 0; //var where to leave result
for (;i>0 && str[i] === '0';i--){
	count++;
}
console.log(count)