Behaviour of unsigned right shift applied to byte variable

Question

Consider the following snip of java code

byte b=(byte) 0xf1;
byte c=(byte)(b>>4);
byte d=(byte) (b>>>4);

output:

<         


        

Answer 1

I'd guess that b is sign extended to int before shifting.

So this might work as expected:

(byte)((0x000000FF & b)>>4)