constexpr function parameters as template arguments

Question

I am playing around with some toy code using c++11 to figure out a bit more about how things work. During this I came across the following issue that simplifies down to:

Answer 1

If your purpose is just to shorten code a bit, in C++14 you can create variable template:

template 
constexpr int addVar = x + y;

cout << addVar<5, 6> << endl; // Works with clang 3.5, fails on GCC 4.9.1

GCC 5 will also support this.