std::map default value for build-in type

Question

Recently, I was confused by the std::map operator[] function. In the MSDN library, it says: \"If the argument key value is not found, then it is inserted along with the defa

Answer 1

 |expression:   | POD type T                               | non-POD type T
 ==================================================================================================
 | new T         | not initialized                          | default-initialized
 | new T()       | always default-initialized               | always default-initialized
 | new T(x)      | always initialized via a constructor     | always initialized via a constructor

As far as i know, stl uses new T() for default values, so it will be default-initialized, in case of int to 0.