Round up to Second Decimal Place in Python

Question

How can I round up a number to the second decimal place in python? For example:

0.022499999999999999

Should round up to 0.03<

Answer 1

def round_up(number, ndigits=None):
    # start by just rounding the number, as sometimes this rounds it up
    result = round(number, ndigits if ndigits else 0)
    if result < number:
        # whoops, the number was rounded down instead, so correct for that
        if ndigits:
            # use the type of number provided, e.g. float, decimal, fraction
            Numerical = type(number)
            # add the digit 1 in the correct decimal place
            result += Numerical(10) ** -ndigits
            # may need to be tweaked slightly if the addition was inexact
            result = round(result, ndigits)
        else:
            result += 1 # same as 10 ** -0 for precision of zero digits
    return result

assert round_up(0.022499999999999999, 2) == 0.03
assert round_up(0.1111111111111000, 2) == 0.12

assert round_up(1.11, 2) == 1.11
assert round_up(1e308, 2) == 1e308