Round up to Second Decimal Place in Python

Question

How can I round up a number to the second decimal place in python? For example:

0.022499999999999999

Should round up to 0.03<

Answer 1

Note that the ceil(num * 100) / 100 trick will crash on some degenerate inputs, like 1e308. This may not come up often but I can tell you it just cost me a couple of days. To avoid this, "it would be nice if" ceil() and floor() took a decimal places argument, like round() does... Meanwhile, anyone know a clean alternative that won't crash on inputs like this? I had some hopes for the decimal package but it seems to die too:

>>> from math import ceil
>>> from decimal import Decimal, ROUND_DOWN, ROUND_UP
>>> num = 0.1111111111000
>>> ceil(num * 100) / 100
0.12
>>> float(Decimal(num).quantize(Decimal('.01'), rounding=ROUND_UP))
0.12
>>> num = 1e308
>>> ceil(num * 100) / 100
Traceback (most recent call last):
  File "", line 301, in runcode
  File "", line 1, in 
OverflowError: cannot convert float infinity to integer
>>> float(Decimal(num).quantize(Decimal('.01'), rounding=ROUND_UP))
Traceback (most recent call last):
  File "", line 301, in runcode
  File "", line 1, in 
decimal.InvalidOperation: []

Of course one might say that crashing is the only sane behavior on such inputs, but I would argue that it's not the rounding but the multiplication that's causing the problem (that's why, eg, 1e306 doesn't crash), and a cleaner implementation of the round-up-nth-place fn would avoid the multiplication hack.