Using grep to get the next WORD after a match in each line

Question

I want to get the \"GET\" queries from my server logs.

For example, this is the server log

1.0.0.127.in-addr.arpa - - [10/Jun/2012          


        

Answer 1

I was trying to do this and came across this link: https://www.unix.com/shell-programming-and-scripting/153101-print-next-word-after-found-pattern.html

Summary: use grep to find matching lines, then use awk to find the pattern and print the next field:

grep pattern logfile | \
  awk '{for(i=1; i<=NF; i++) if($i~/pattern/) print $(i+1)}'

If you want to know the unique occurrences:

grep pattern logfile | \
  awk '{for(i=1; i<=NF; i++) if($i~/pattern/) print $(i+1)}' | \
  sort | \
  uniq -c