Remove duplicate chars using regex?

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情书的邮戳
情书的邮戳 2020-11-30 06:17

Let\'s say I want to remove all duplicate chars (of a particular char) in a string using regular expressions. This is simple -

import re
re.sub(\"a*\", \"a\         


        
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  •  北荒
    北荒 (楼主)
    2020-11-30 06:37

    >>> import re
    >>> re.sub(r'([a-z])\1+', r'\1', 'ffffffbbbbbbbqqq')
    'fbq'
    

    The () around the [a-z] specify a capture group, and then the \1 (a backreference) in both the pattern and the replacement refer to the contents of the first capture group.

    Thus, the regex reads "find a letter, followed by one or more occurrences of that same letter" and then entire found portion is replaced with a single occurrence of the found letter.

    On side note...

    Your example code for just a is actually buggy:

    >>> re.sub('a*', 'a', 'aaabbbccc')
    'abababacacaca'
    

    You really would want to use 'a+' for your regex instead of 'a*', since the * operator matches "0 or more" occurrences, and thus will match empty strings in between two non-a characters, whereas the + operator matches "1 or more".

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