How can i order threads in the order they were instantiated.e.g. how can i make the below program print the numbers 1...10 in order.
public class ThreadOrder
Control of thread execution order may be implemented quite easily with the semaphores. The code attached is based on the ideas presented in Schildt's book on Java (The complete reference....). // Based on the ideas presented in: // Schildt H.: Java.The.Complete.Reference.9th.Edition.
import java.util.concurrent.Semaphore;
class Manager {
int n;
// Initially red on semaphores 2&3; green semaphore 1.
static Semaphore SemFirst = new Semaphore(1);
static Semaphore SemSecond = new Semaphore(0);
static Semaphore SemThird = new Semaphore(0);
void firstAction () {
try {
SemFirst.acquire();
} catch(InterruptedException e) {
System.out.println("Exception InterruptedException catched");
}
System.out.println("First: " );
System.out.println("-----> 111");
SemSecond.release();
}
void secondAction() {
try{
SemSecond.acquire();
} catch(InterruptedException e) {
System.out.println("Exception InterruptedException catched");
}
System.out.println("Second: ");
System.out.println("-----> 222");
SemThird.release();
}
void thirdAction() {
try{
SemThird.acquire();
} catch(InterruptedException e) {
System.out.println("Exception InterruptedException catched");
}
System.out.println("Third: ");
System.out.println("-----> 333");
SemFirst.release();
}
}
class Thread1 implements Runnable {
Manager q;
Thread1(Manager q) {
this.q = q;
new Thread(this, "Thread1").start();
}
public void run() {
q.firstAction();
}
}
class Thread2 implements Runnable {
Manager q;
Thread2(Manager q) {
this.q = q;
new Thread(this, "Thread2").start();
}
public void run() {
q.secondAction();
}
}
class Thread3 implements Runnable {
Manager q;
Thread3(Manager q) {
this.q = q;
new Thread(this, "Thread3").start();
}
public void run() {
q.thirdAction();
}
}
class ThreadOrder {
public static void main(String args[]) {
Manager q = new Manager();
new Thread3(q);
new Thread2(q);
new Thread1(q);
}
}