Ordering threads to run in the order they were created/started

Question

How can i order threads in the order they were instantiated.e.g. how can i make the below program print the numbers 1...10 in order.

public class ThreadOrder         


        

Answer 1

Sounds like you want ExecutorService.invokeAll, which will return results from worker threads in a fixed order, even though they may be scheduled in arbitrary order:

import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.Callable;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

public class ThreadOrdering {

    static int NUM_THREADS = 10;

    public static void main(String[] args) {
        ExecutorService exec = Executors.newFixedThreadPool(NUM_THREADS);
        class MyCallable implements Callable {
            private final int threadnumber;

            MyCallable(int threadnumber){
                this.threadnumber = threadnumber;
            }

            public Integer call() {
                System.out.println("Running thread #" + threadnumber);
                return threadnumber;
            }
        }

        List> callables =
            new ArrayList>();
        for(int i=1; i<=NUM_THREADS; i++) {
            callables.add(new MyCallable(i));
        }
        try {
            List> results =
                exec.invokeAll(callables);
            for(Future result: results) {
                System.out.println("Got result of thread #" + result.get());
            }
        } catch (InterruptedException ex) {
            ex.printStackTrace();
        } catch (ExecutionException ex) {
            ex.printStackTrace();
        } finally {
            exec.shutdownNow();
        }
    }

}