Check if an array is sorted, return true or false

Question

I am writing an easy program the just returns true if an array is sorted else false and I keep getting an exception in eclipse and I just can\'t figure out why. I was wonder

Answer 1

You shouldn't use a[i+1] because that value may or may not go off the array.

For example:

A = {1, 2, 3}
// A.length is 3.
for(i = 0; i < a.length; i ++) // A goes up to 3, so A[i+1] = A[4]

To fix this, simply stop the loop one early.

int i;
for(i = 0; i < a.length - 1; i ++);{

    if (a[i] < a[i+1]) {

        return true;
    }else{
        return false;

    }

}