When is a type in c++11 allowed to be memcpyed?

Question

My question is the following:

If I want to copy a class type, memcpy can do it very fast. This is allowed in some situations.

We have some type traits:

Answer 1

If is_trivally_copyable::value (or in C++14 is_trivially_copyable(), or in C++17 is_trivially_copyable_v) is not zero, the type is copyable using memcpy.

Per the C++ standard, a type being trivially copyable means:

the underlying bytes making up the object can be copied into an array of char or unsigned char. If the content of the array of char or unsigned char is copied back into the object, the object shall subsequently hold its original value.

However, it is important to realise that pointers are trivially copyable types, too. Whenever there are pointer inside the data structures you will be copying, you have to brainually make sure that copying them around is proper.

Examples where hazard may be caused by just relying on the object being trivially copyable:

• A tree-structure implementation where your data is placed in a contiguous region of memory, but with nodes storing absolute addresses to child nodes
• Creating multiple instances of some data for sake of multithreading performance (in order to reduce cache crashes), with owning pointers inside, pointing anywhere
• You have a flat object without pointers, but with an embedded third party structure inside. The third party structure at some point in the future includes a pointer that should not exist twice or more.

So whenever memcopying, keep in mind to check whether pointers could be copied in that specific case, and if that would be okay.

Realise that is_trivially_copyable is only the "Syntax Check", not the "Semantic Test", in compiler parlance.