Simplest and most efficient is to sum up logarithms. If you use Log10 you get power and exponent.
Pseudocode
r=0
for i from 1 to n
r= r + log(i)/log(10)
print "result is:", 10^(r-floor(r)) ,"*10^" , floor(r)
You might need to add the code so the integer part does not increase too much and thus decrease accuracy, but result should be ok for even very large factorials.