How to find out if letter is Alphanumeric or Digit in Swift

Question

I want to count the number of letters, digits and special characters in the following string:

let phrase = \"The final score was 32-31!\"

I

Answer 1

For Swift 5 you can do the following for simple strings, but be vigilant about handling characters like "1️⃣" , "④" these would be treated as numbers as well.

let phrase = "The final score was 32-31!"

var numberOfDigits = 0;
var numberOfLetters = 0;
var numberOfSymbols = 0;

phrase.forEach {

    if ($0.isNumber) {
        numberOfDigits += 1;
    }
    else if ($0.isLetter)  {
        numberOfLetters += 1
    }
    else if ($0.isSymbol || $0.isPunctuation || $0.isCurrencySymbol || $0.isMathSymbol) {
        numberOfSymbols += 1;
    }
}

print(#"\#(numberOfDigits)  || \#(numberOfLetters) || \#(numberOfSymbols)"#);