Print floating point values without leading zero

Question

Trying to use a format specifier to print a float that will be less than 1 without the leading zero. I came up with a bit of a hack but I assume there is a way to just drop

Answer 1

I am surprised nobody suggested a more mathematical way to do it:

n = 0.123456789
'.%d' % (n*1e4)

Looks much nicer to me. :)

But interestingly yours is the fastest.

$ python -mtimeit '".%d" % (0.123456789*1e4)'
1000000 loops, best of 3: 0.809 usec per loop
$ python -mtimeit '("%.4f"%(0.123456789)).lstrip("0")'
1000000 loops, best of 3: 0.209 usec per loop
$ python -mtimeit '("%.4f"%(0.123456789))[1:]'
10000000 loops, best of 3: 0.0723 usec per loop