Split string at nth occurrence of a given character

Question

Is there a Python-way to split a string after the nth occurrence of a given delimiter?

Given a string:

\'20_231_myString_234\'

It s

Answer 1

I had a larger string to split ever nth character, ended up with the following code:

# Split every 6 spaces
n = 6
sep = ' '
n_split_groups = []

groups = err_str.split(sep)
while len(groups):
    n_split_groups.append(sep.join(groups[:n]))
    groups = groups[n:]

print n_split_groups

Thanks @perreal!