Split string at nth occurrence of a given character

Question

Is there a Python-way to split a string after the nth occurrence of a given delimiter?

Given a string:

\'20_231_myString_234\'

It s

Answer 1

I like this solution because it works without any actuall regex and can easiely be adapted to another "nth" or delimiter.

import re

string = "20_231_myString_234"
occur = 2  # on which occourence you want to split

indices = [x.start() for x in re.finditer("_", string)]
part1 = string[0:indices[occur-1]]
part2 = string[indices[occur-1]+1:]

print (part1, ' ', part2)