Overflow Error in Python's numpy.exp function

Question

I want to use numpy.exp like this:

cc = np.array([
    [0.120,0.34,-1234.1]
])

print 1/(1+np.exp(-cc))

But this gives me erro

Answer 1

A possible solution is to use the decimal module, which lets you work with arbitrary precision floats. Here is an example where a numpy array of floats with 100 digits precision is used:

import numpy as np
import decimal

# Precision to use
decimal.getcontext().prec = 100

# Original array
cc = np.array(
    [0.120,0.34,-1234.1]
)
# Fails
print(1/(1 + np.exp(-cc)))    

# New array with the specified precision
ccd = np.asarray([decimal.Decimal(el) for el in cc], dtype=object)
# Works!
print(1/(1 + np.exp(-ccd)))