Parse ifconfig to get only my IP address using Bash

Question

I want to edit the bashrc file to have a simple function called \"myip\" to run. As you might guess, the function myip prints only my internal IP address of my machine.

Answer 1

A simple AWK + Bash script example which may give general idea how to parse command output and mix syntaxes together.

Full code is at: https://gist.github.com/darkphase/67d7ec22d47dbebd329e

BEGIN { RS = "" ; FS = "\n" }  # Change separator characters
{
    while ( "'"$cmd"'" | getline ){
        # print $0
        if ( $1 !~ /LOOPBACK/ ){

            split($1,arr," ")
            print "'"$blue"'"arr[1]"'"$reset"'"

            for(i = 1; i <= NF; i++) { # Loop through fields (this case lines)
                split($i,arr," ")
                switch ( arr[1] ) {
                    case "inet":
                        print "'"$red"'" "IPV4:" "'"$reset"'" "\n IP: " "'"$yellow"'" arr[2] "'"$reset"'" "\n NM: "arr[4]"\n BC: "arr[6]
                        break
                    case "inet6":
                        print "'"$red"'" "IPV6:" "'"$reset"'" "\n IP: "arr[2]"\n PL: "arr[4]
                        break
                    case "ether":
                        print "'"$red"'" "MAC: " "'"$reset"'" arr[2]
                        break
                    default:
                }
            }
            print ""
        }
    }
}'