Parse ifconfig to get only my IP address using Bash

Question

I want to edit the bashrc file to have a simple function called \"myip\" to run. As you might guess, the function myip prints only my internal IP address of my machine.

Answer 1

You can also try this

user@linux:~$ cat script.sh
ifconfig | grep ad.*Bc | cut -d: -f2 | awk '{ print $1}'
user@linux:~$ 

Output

user@linux:~$ ./script.sh
192.168.1.1
10.0.1.1
user@linux:~$

Please take note that ifconfig output might be different depending on your linux version. Hence, you might want to change the script accordingly.

Btw, this is my ifconfig output

user@linux:~$ ifconfig 
eth0      Link encap:Ethernet  HWaddr 00:00:00:00:00:10  
          inet addr:192.168.1.1  Bcast:192.168.56.255  Mask:255.255.255.0
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:112 errors:0 dropped:0 overruns:0 frame:0
          TX packets:93 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000 
          RX bytes:14616 (14.2 KiB)  TX bytes:17776 (17.3 KiB)

eth1      Link encap:Ethernet  HWaddr 00:00:00:00:00:11
          inet addr:10.0.1.1  Bcast:10.0.1.255  Mask:255.255.255.0
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:0 errors:0 dropped:0 overruns:0 frame:0
          TX packets:0 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000 
          RX bytes:0 (0.0 B)  TX bytes:0 (0.0 B)

user@linux:~$