Why subclass in another package cannot access a protected method?

Question

I have two classes in two different packages:

package package1;

public class Class1 {
    public void tryMePublic() {
    }

    protected void tryMeProtect         


        

Answer 1

Protected methods can only be accessible through inheritance in subclasses outside the package. And hence the second approach tryMeProtected(); works.

The code below wont compile because we are not calling the inherited version of protected method.

 Class1 c = new Class1();
 c.tryMeProtected(); // ERROR: tryMeProtected() has protected access in Class1

Follow this stackoverflow link for more explaination.