I have the following code to make an unordered_set. This compiles fine.
struct Interval {
unsigned int begin;
unsigned int e
First problem:
You are passing string as the second template argument for your instantiation of the unordered_set<> class template. The second argument should be the type of your hasher functor, and std::string is not a callable object.
Perhaps meant to write:
unordered_set test;
// ^^^^^^^^^^^^
// Why this?
Also, I would suggest using names other than begin and end for your (member) variables, since those are names of algorithms of the C++ Standard Library.
Second problem:
You should keep in mind, that the hasher function should be qualified as const, so your functor should be:
struct Hash {
size_t operator() (const Interval &interval) const {
// ^^^^^
// Don't forget this!
string temp = to_string(interval.b) +
to_string(interval.e) +
to_string(interval.proteinIndex);
return (temp.length());
}
};
Third problem:
Finally, if you want std::unordered_set to be able to work with objects of type Interval, you need to define an equality operator consistent with your hash function. By default, if you do not specify any type argument as the third parameter of the std::unordered_set class template, operator == will be used.
You currently do not have any overload of operator == for your class Interval, so you should provide one. For example:
inline bool operator == (Interval const& lhs, Interval const& rhs)
{
return (lhs.b == rhs.b) &&
(lhs.e == rhs.e) &&
(lhs.proteinIndex == rhs.proteinIndex);
}
Conclusion:
After all the above modifications, you can see your code compiling in this live example.