g++ How to get warning on ignoring function return value

Question

lint produces some warning like:

foo.c XXX Warning 534: Ignoring return value of function bar()

From the lint manual

Answer 1

Thanks to WhirlWind and paxdiablo for the answer and comment. Here is my attempt to put the pieces together into a complete (?) answer.

-Wunused-result is the relevant gcc option. And it is turned on by default. Quoting from gcc warning options page:

-Wno-unused-result

Do not warn if a caller of a function marked with attribute warn_unused_result (see Variable Attributes) does not use its return value. The default is -Wunused-result

So, the solution is to apply the warn_unused_result attribute on the function.

Here is a full example. The contents of the file unused_result.c

int foo() { return 3; }

int bar() __attribute__((warn_unused_result));
int bar() { return 5; }

int main()
{
    foo();
    bar();    /* line 9 */
    return 0;
}

and corresponding compilation result:

$gcc unused_result.c 
unused_result.c: In function ‘main’:
unused_result.c:9: warning: ignoring return value of ‘bar’, declared with attribute warn_unused_result

Note again that it is not necessary to have -Wunused-result since it is default. One may be tempted to explicitly mention it to communicate the intent. Though that is a noble intent, but after analyzing the situation, my choice, however, would be against that. Because, having -Wunused-result in the compile options may generate a false sense of security/satisfaction which is not true unless the all the functions in the code base are qualified with warn_unused_result.