Convert a two byte UInt8 array to a UInt16 in Swift

Question

With Swift I want to convert bytes from a uint8_t array to an integer.

\"C\" Example:

char bytes[2] = {0x01, 0x02};
NSData *data = [NSData dataWithBy         


        

Answer 1

In Swift 5 or later you can convert the bytes [UInt8] to UInt16 value using withUnsafeBytes { $0.load(as: UInt16.self) }

let bytes: [UInt8] = [1, 2]

loading as UInt16

let uint16 = bytes.withUnsafeBytes { $0.load(as: UInt16.self) } 

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To get rid of the verbosity we can create a generic method extending ContiguousBytes:

extension ContiguousBytes {
    func object() -> T { withUnsafeBytes { $0.load(as: T.self) } }
}

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Usage:

let bytes: [UInt8] = [1, 2]
let uint16: UInt16 = bytes.object()  // 513