How to take all but the last element in a sequence using LINQ?

Question

Let\'s say I have a sequence.

IEnumerable sequence = GetSequenceFromExpensiveSource();
// sequence now contains: 0,1,2,3,...,999999,1000000
         


        

Answer 1

My traditional IEnumerable approach:

/// 

/// Skips first element of an IEnumerable
/// 
/// Enumerable type
/// The enumerable
/// IEnumerable of type skipping first element
private IEnumerable SkipFirstEnumerable(IEnumerable models)
{
    using (var e = models.GetEnumerator())
    {
        if (!e.MoveNext()) return;
        for (;e.MoveNext();) yield return e.Current;
        yield return e.Current;
    }
}

/// 

/// Skips last element of an IEnumerable
/// 
/// Enumerable type
/// The enumerable
/// IEnumerable of type skipping last element
private IEnumerable SkipLastEnumerable(IEnumerable models)
{
    using (var e = models.GetEnumerator())
    {
        if (!e.MoveNext()) return;
        yield return e.Current;
        for (;e.MoveNext();) yield return e.Current;
    }
}