How to take all but the last element in a sequence using LINQ?

Question

Let\'s say I have a sequence.

IEnumerable sequence = GetSequenceFromExpensiveSource();
// sequence now contains: 0,1,2,3,...,999999,1000000
         


        

Answer 1

The Enumerable.SkipLast(IEnumerable, Int32) method was added in .NET Standard 2.1. It does exactly what you want.

IEnumerable sequence = GetSequenceFromExpensiveSource();

var allExceptLast = sequence.SkipLast(1);

From https://docs.microsoft.com/en-us/dotnet/api/system.linq.enumerable.skiplast

Returns a new enumerable collection that contains the elements from source with the last count elements of the source collection omitted.