Iterate over nested dictionary

Question

Is there an easy way of iterating over nested dictionary, which may consist of other objects like lists, tuples, then again dictionaries so that iteration covers all the ele

Answer 1

Here is another solution,

#!/usr/bin/python

d = {'key_1': 'value_1',
     'key_2': {'key_21': [(2100, 2101), (2110, 2111)],
           'key_22': ['l1', 'l2'],
           'key_23': {'key_231': 'v'},
           'key_24': {'key_241': 502,
                      'key_242': [(5, 0), (7, 0)],
                      'key_243': {'key_2431': [0, 0],
                                  'key_2432': 504,
                                  'key_2433': [(11451, 0), (11452, 0)]},
                      'key_244': {'key_2441': ['ll1', 'll2']}}}}

def search_it(nested, target):
    found = []
    for key, value in nested.iteritems():
        if key == target:
            found.append(value)
        elif isinstance(value, dict):
            found.extend(search_it(value, target))
        elif isinstance(value, list):
            for item in value:
                if isinstance(item, dict):
                    found.extend(search_it(item, target))
        else:
            if key == target:
                found.append(value)
    return found

keys = [ 'key_242', 'key_243', 'key_242', 'key_244', 'key_1' ]

for key in keys:
    f = search_it(d, key)
    print 'Key: %s, value: %s' % (key, f[0])

Output:

Key: key_242, value: [(5, 0), (7, 0)]
Key: key_243, value: {'key_2433': [(11451, 0), (11452, 0)], 'key_2432': 504, 'key_2431': 
 [0, 0]}
Key: key_242, value: [(5, 0), (7, 0)]
Key: key_244, value: {'key_2441': ['ll1', 'll2']}
Key: key_1, value: value_1