How can I compare two strings in java and define which of them is smaller than the other alphabetically?

Question

I want to use the binary search algorithm to search the string which has been entered by the user in a very big sorted file. I can not compare the string which has been ente

Answer 1

If you would like to ignore case you could use the following:

String s = "yip";
String best = "yodel";
int compare = s.compareToIgnoreCase(best);
if(compare < 0){
    //-1, --> s is less than best. ( s comes alphabetically first)
}
else if(compare > 0 ){
// best comes alphabetically first.
}
else{
    // strings are equal.
}