How to print 5 consecutive lines after a pattern in file using awk [duplicate]

Answer 1

Edit: didn't notice PATTERN shouldn't be part of the output.

cat /etc/passwd | awk '{if(a-->0){print;next}} /qmaild/{a=5}'

or

cat /etc/passwd | awk ' found && NR-6 < a{print} /qmaild/{a=NR;found=1}'

The shortest I can come up with is:

cat /etc/passwd | awk 'a-->0;/qmaild/{a=5}'

Read as a tends to 0. /qmaild/ sets a to 5 :-)