How to know if urllib.urlretrieve succeeds?

Question

urllib.urlretrieve returns silently even if the file doesn\'t exist on the remote http server, it just saves a html page to the named file. For example:

Answer 1

You can create a new URLopener (inherit from FancyURLopener) and throw exceptions or handle errors any way you want. Unfortunately, FancyURLopener ignores 404 and other errors. See this question:

How to catch 404 error in urllib.urlretrieve