I have always wanted to do this but every time I start thinking about the problem it blows my mind because of its exponential nature.
The problem solver I want to be
Input is obviously a set of digits and operators: D={1,3,3,6,7,8,3} and Op={+,-,*,/}. The most straight forward algorithm would be a brute force solver, which enumerates all possible combinations of these sets. Where the elements of set Op can be used as often as wanted, but elements from set D are used exactly once. Pseudo code:
D={1,3,3,6,7,8,3}
Op={+,-,*,/}
Solution=348
for each permutation D_ of D:
for each binary tree T with D_ as its leafs:
for each sequence of operators Op_ from Op with length |D_|-1:
label each inner tree node with operators from Op_
result = compute T using infix traversal
if result==Solution
return T
return nil
Other than that: read jedrus07's and HPM's answers.