PHP function use variable from outside

Question

function parts($part) { 
    $structure = \'http://\' . $site_url . \'content/\'; 
    echo($tructure . $part . \'.php\'); 
}

This function uses a

Answer 1

Alternatively, you can bring variables in from the outside scope by using closures with the use keyword.

$myVar = "foo";
$myFunction = function($arg1, $arg2) use ($myVar)
{
 return $arg1 . $myVar . $arg2;
};