How to increment version number in a shell script?

Question

The following simple version control script is meant to find the last version number of a given file, increment it, run a given command with the newly created file (e.g., ed

Answer 1

1. Only increment the selected part

Usage

increment_version 1.39.0 0 # 2.39.0
increment_version 1.39.0 1 # 1.40.0
increment_version 1.39.0 2 # 1.39.1

Code

### Increments the part of the string
## $1: version itself
## $2: number of part: 0 – major, 1 – minor, 2 – patch
increment_version() {
  local delimiter=.
  local array=($(echo "$1" | tr $delimiter '\n'))
  array[$2]=$((array[$2]+1))
  echo $(local IFS=$delimiter ; echo "${array[*]}")
}

Simplified version of @dimpiax answer

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EDIT: I created another version of this script that put zeros on the less important parts if the most important ones are changed. Just note the diferent expected results on the usage part.

2. Increment the selected part and put zeros on the subsequent parts

Usage

increment_version 1.39.3 0 # 2.0.0
increment_version 1.39.3 1 # 1.40.0
increment_version 1.39.3 2 # 1.39.4

#!/bin/bash

### Increments the part of the string
## $1: version itself
## $2: number of part: 0 – major, 1 – minor, 2 – patch

increment_version() {
  local delimiter=.
  local array=($(echo "$1" | tr $delimiter '\n'))
  array[$2]=$((array[$2]+1))
  if [ $2 -lt 2 ]; then array[2]=0; fi
  if [ $2 -lt 1 ]; then array[1]=0; fi
  echo $(local IFS=$delimiter ; echo "${array[*]}")
}