Initialization difference with or without Curly braces in C++11

Question

We can initialize the variable in two ways in C++11

One:

int abc = 7;

Two:

int ab         


        

Answer 1

The first is the copy initialization, while the second is list initialization.

But, usually copy initialization is less used. Because, if you're doing it by passing objects of user defined types, it just causes bitcopy & hence may not produce intended results if the user defined class uses pointers.