iOS 4.2 - Return to app after phone call

Question

I can successfully initiate a phone call within my app using the following:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@\"tel://12345678         


        

Answer 1

With iOS 9.3.4, every technique that I try has control return to the calling app after the phone call. Has this behavior changed recently? This example is just a Swift and simplified version of https://github.com/jatraiz/RZTelpromptExample:

class ViewController: UIViewController {

    let phoneNumber = "7204790465"

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    @IBAction func callWithTelPushed(sender: AnyObject) {
        if let url = NSURL(string: "tel:" + self.phoneNumber) {
            UIApplication.sharedApplication().openURL(url)
        }
    }

    @IBAction func callWithTelpromptPushed(sender: AnyObject) {
        if let url = NSURL(string: "telprompt:" + self.phoneNumber) {
            UIApplication.sharedApplication().openURL(url)
        }
    }

    @IBAction func callWithRZTelpromptPushed(sender: AnyObject) {
        RZTelprompt.callWithString(self.phoneNumber)
    }
}