android color between two colors, based on percentage?

Question

I would like to calculate the color depending on a percentage value:

float percentage = x/total;
int color;
if (percentage >= 0.95) {
  color = Color.GREE         


        

Answer 1

Ok, after 2 hours of converting to yuv, hsv, etc pp... I give up. I now do it just like this:

public class ColorUtils {
    private static int FIRST_COLOR = Color.GREEN;
    private static int SECOND_COLOR = Color.YELLOW;
    private static int THIRD_COLOR = Color.RED;

    public static int getColor(float p) {
        int c0;
        int c1;
        if (p <= 0.5f) {
            p *= 2;
            c0 = FIRST_COLOR;
            c1 = SECOND_COLOR;
        } else {
            p = (p - 0.5f) * 2;
            c0 = SECOND_COLOR;
            c1 = THIRD_COLOR;
        }
        int a = ave(Color.alpha(c0), Color.alpha(c1), p);
        int r = ave(Color.red(c0), Color.red(c1), p);
        int g = ave(Color.green(c0), Color.green(c1), p);
        int b = ave(Color.blue(c0), Color.blue(c1), p);
        return Color.argb(a, r, g, b);
    }

    private static int ave(int src, int dst, float p) {
        return src + java.lang.Math.round(p * (dst - src));
    }
}

By explicity using yellow as the middle color, the generated colors are brighter :-)

Anyway.. if someone has a good other solution, I would appreciate it.