setTimeout callback argument

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伪装坚强ぢ
伪装坚强ぢ 2020-11-29 22:20

Let\'s consider this piece of JavaScript:

function Person(name) {
    this.name = name;
}

Person.prototype.showName = function() {
    alert(this.name);
}

         


        
4条回答
  •  旧时难觅i
    2020-11-29 23:01

    Your question really has nothing at all to do with setTimeout. You simply need to understand the difference between a function call and a reference to a function.

    Consider these four assignments:

    var one = function() { mike.showName(); };
    var two = mike.showName;
    var three = mike.showName();
    var four = (function() { mike.showName(); })();
    

    The first two assign a reference to a function to their respective variables. The last two, however, call functions (that's what the parens are for) and assign their return values to the vars on the left-hand side.

    How this relates to setTimeout:

    The setTimeout function expects as its first argument a reference to a function, so either one or two above would be correct, but three and four would not. However, it is important to note that it is not, strictly speaking, a mistake to pass the return value of a function to setTimeout, although you'll frequently see that said.

    This is perfectly fine, for example:

    function makeTimeoutFunc(param) {
        return function() {
            // does something with param
        }
    }
    
    setTimeout(makeTimeoutFunc(), 5000);
    

    It has nothing to do with how setTimeout receives a function as its argument, but that it does.

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