Why default constructor is required in a parent class if it has an argument-ed constructor?

Question

Why default constructor is required(explicitly) in a parent class if it has an argumented constructor

class A {    
  A(int i){    
  }
}

class B extends          


        

Answer 1

When extending a class, the default superclass constructor is automatically added.

public class SuperClass {
}

public class SubClass extends SuperClass {
   public SubClass(String s, Product... someProducts) {
      //super(); <-- Java automatically adds the default super constructor
   }
}

If you've overloaded your super class constructor, however, this takes the place of the default and invoking super() will thus cause a compile error as it is no longer available. You must then explicitly add in the overloaded constructor or create a no-parameter constructor. See below for examples:

public class SuperClass {
   public SuperClass(String s, int x) {
     // some code
   }
}

public class SubClass extends SuperClass {
   public SubClass(String s, Product... someProducts) {
      super("some string", 1);
   }
}

OR...

public class SuperClass {
   public SuperClass() {
     // can be left empty.
   }
}

public class SubClass extends SuperClass {
   public SubClass(String s, Product... someProducts) {
      //super(); <-- Java automatically adds the no-parameter super constructor
   }
}