Pipe output to bash function

Question

I have as simple function in a bash script and I would like to pipe stdout to it as an input.

jc_hms(){
  printf \"$1\"
}

I\'d like to use

Answer 1

I like user.friendly's answer using the Bash built-in conditional unset substitution syntax. Here's a slight tweak to make his answer more generic, such as for cases with an indeterminate parameter count:

function myfunc() {
    declare MY_INPUT=${*:-$(