Pipe output to bash function

Question

I have as simple function in a bash script and I would like to pipe stdout to it as an input.

jc_hms(){
  printf \"$1\"
}

I\'d like to use

Answer 1

1) I know this is a pretty old post

2) I like most of the answers here

However, I found this post because I needed to something similar. While everyone agrees stdin is what needs to be used, what the answers here are missing is the actual usage of the /dev/stdin file.

Using the read builtin forces this function to be used with piped input, so it can no longer be used in a typical way. I think utilizing /dev/stdin is a superior way of solving this problem, so I wanted to add my 2 cents for completeness.

My solution:

jc_hms() { 
  declare -i i=${1:-$(

In action:

user@hostname:pwd$ jc_hms 7800
02:10:00
user@hostname:pwd$ echo 7800 | jc_hms 
02:10:00

I hope this may help someone.

Happy hacking!