Why does the Scala compiler disallow overloaded methods with default arguments?

Question

While there might be valid cases where such method overloadings could become ambiguous, why does the compiler disallow code which is neither ambiguous at compile time nor at

Answer 1

One of the possible scenario is

  def foo(a: Int)(b: Int = 10)(c: String = "10") = a + b + c
  def foo(a: Int)(b: String = "10")(c: Int = 10) = a + b + c

The compiler will be confused about which one to call. In prevention of other possible dangers, the compiler would allow at most one overloaded method has default arguments.

Just my guess:-)