How to get the file-path of the currently executing javascript code

Question

I\'m trying to do something like a C #include \"filename.c\", or PHP include(dirname(__FILE__).\"filename.php\") but in javascript. I know I can do

Answer 1

Refining upon the answers found here I came up with the following:

getCurrentScript.js

var getCurrentScript = function () {
  if (document.currentScript) {
    return document.currentScript.src;
  } else {
    var scripts = document.getElementsByTagName('script');
    return scripts[scripts.length-1].src;

  }
};

module.exports = getCurrentScript;

getCurrentScriptPath.js

var getCurrentScript = require('./getCurrentScript');

var getCurrentScriptPath = function () {
  var script = getCurrentScript();
  var path = script.substring(0, script.lastIndexOf('/'));
  return path;
};

module.exports = getCurrentScriptPath;

BTW: I'm using CommonJS module format and bundling with webpack.