How to open file using argparse?

Question

I want to open file for reading using argparse. In cmd it must look like: my_program.py /filepath

That\'s my try:

parser = argparse.ArgumentParser()
         


        

Answer 1

I'll just add the option to use pathlib:

import argparse, pathlib

parser = argparse.ArgumentParser()
parser.add_argument('file', type=pathlib.Path)
args = parser.parse_args()

with args.file.open('r') as file:
    print(file.read())