How to open file using argparse?

Question

I want to open file for reading using argparse. In cmd it must look like: my_program.py /filepath

That\'s my try:

parser = argparse.ArgumentParser()
         


        

Answer 1

In order to have the file closed gracefully, you can combine argparse.FileType with the "with" statement

# ....

parser.add_argument('file', type=argparse.FileType('r'))
args = parser.parse_args()

with args.file as file:
    print file.read()

--- update ---

Oh, @Wernight already said that in comments