Is there a way to write a bash function which aborts the whole execution, no matter how it is called?

Question

I was using \"exit 1\" statement in my bash functions to terminate the whole script and it worked fine:

function func()
{
   echo \"Goodbye\"
   exit 1
}
ech         


        

Answer 1

A child process can't force the parent process to close implicitly. You need to use some kind of signaling mechanism. Options might include a special return value, or perhaps sending some signal with kill, something like

function child() {
    local parent_pid="$1"
    local other="$2"
    ...
    if [[ $failed ]]; then
        kill -QUIT "$parent_pid"
    fi
}