Bash script absolute path with OS X

Question

I am trying to obtain the absolute path to the currently running script on OS X.

I saw many replies going for readlink -f $0. However since OS X\'s

Answer 1

Based on the communication with commenter, I agreed that it is very hard and has no trival way to implement a realpath behaves totally same as Ubuntu.

But the following version, can handle corner cases best answer can't and satisfy my daily needs on macbook. Put this code into your ~/.bashrc and remember:

• arg can only be 1 file or dir, no wildcard
• no spaces in the dir or file name
• at least the file or dir's parent dir exists
• feel free to use . .. / thing, these are safe

---

    # 1. if is a dir, try cd and pwd
    # 2. if is a file, try cd its parent and concat dir+file
    realpath() {
     [ "$1" = "" ] && return 1

     dir=`dirname "$1"`
     file=`basename "$1"`

     last=`pwd`

     [ -d "$dir" ] && cd $dir || return 1
     if [ -d "$file" ];
     then
       # case 1
       cd $file && pwd || return 1
     else
       # case 2
       echo `pwd`/$file | sed 's/\/\//\//g'
     fi

     cd $last
    }