Print a file's last modified date in Bash

Question

I can\'t seem to find how to print out the date of a file. I\'m so far able to print out all the files in a directory, but I need to print out the dates with it.

I

Answer 1

On OS X, I like my date to be in the format of YYYY-MM-DD HH:MM in the output for the file.

So to specify a file I would use:

stat -f "%Sm" -t "%Y-%m-%d %H:%M" [filename]

If I want to run it on a range of files, I can do something like this:

#!/usr/bin/env bash
for i in /var/log/*.out; do
  stat -f "%Sm" -t "%Y-%m-%d %H:%M" "$i"
done

This example will print out the last time I ran the sudo periodic daily weekly monthly command as it references the log files.

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To add the filenames under each date, I would run the following instead:

#!/usr/bin/env bash
for i in /var/log/*.out; do
  stat -f "%Sm" -t "%Y-%m-%d %H:%M" "$i"
  echo "$i"
done

The output would was the following:

2016-40-01 16:40
/var/log/daily.out
2016-40-01 16:40
/var/log/monthly.out
2016-40-01 16:40
/var/log/weekly.out

Unfortunately I'm not sure how to prevent the line break and keep the file name appended to the end of the date without adding more lines to the script.

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PS - I use #!/usr/bin/env bash as I'm a Python user by day, and have different versions of bash installed on my system instead of #!/bin/bash