Return first N key:value pairs from dict

Question

Consider the following dictionary, d:

d = {\'a\': 3, \'b\': 2, \'c\': 3, \'d\': 4, \'e\': 5}

I want to return the first N key:value pairs f

Answer 1

Did not see it on here. Will not be ordered but the simplest syntactically if you need to just take some elements from a dictionary.

n = 2
{key:value for key,value in d.items()[0:n]}