How to print matched regex pattern using awk?

Question

Using awk, I need to find a word in a file that matches a regex pattern.

I only want to print the word matched with the pattern.

So if

Answer 1

Off topic, this can be done using the grep also, just posting it here in case if anyone is looking for grep solution

echo 'xxx yyy zzze ' | grep -oE 'yyy'